Electrical Calculations for Apprentices: Every Formula Explained Simply
Electrical calculations do not need to be intimidating. This guide covers every essential calculation in the apprenticeship — Ohm's law, power triangle, cable sizing, voltage drop, diversity, and fault current — in plain English with worked examples you can follow.
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Key Takeaways
1Ohm's law (V = I x R) and the power formula (P = V x I) are the foundation of every electrical calculation. If you understand these two equations, you can work out almost anything.
2Cable sizing is not just about current capacity. You must also check voltage drop, disconnection time (using Zs), and thermal constraints (adiabatic equation) before selecting a cable.
3Voltage drop must not exceed 3% for lighting circuits and 5% for other circuits in most domestic installations, as recommended by BS 7671 Appendix 4.
4Diversity allows you to reduce the assumed maximum demand on a circuit or distribution board because not all loads operate at maximum simultaneously. IET guidance provides standard diversity factors.
5Elec-Mate provides 46+ courses, flashcards, mock exams, and an AI tutor that can walk you through any calculation step by step with worked examples.
01 · Apprentice Guide
Why Electrical Calculations Matter
Electrical calculations are not just academic exercises for passing exams. They are the tools you use to design safe, compliant circuits. Every cable you select, every protective device you specify, and every test result you interpret depends on your ability to apply basic electrical calculations correctly.
As an electrical apprentice, you will encounter calculations in your Level 3 qualification, 18th Edition exam (C&G 2382), inspection and testing qualification (C&G 2391), and in the EPA professional discussion. You do not need to be a mathematician. You need to understand a handful of core equations and know how to apply them to real situations.
This guide covers the essential calculations in simple terms, with worked examples that show you how each calculation applies on a real job site. If you can master these, you will be well-prepared for every exam and assessment in the apprenticeship.
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02 · Apprentice Guide
Ohm's Law: The One Equation You Must Know
Ohm's law is the foundation of electrical science. It describes the relationship between three quantities that you will work with every day:
V = I x R
Voltage (V, volts) = Current (I, amps) x Resistance (R, ohms)
This single equation can be rearranged to find any of the three values if you know the other two:
Find Voltage
V = I x R
"How much voltage is needed to push 10A through 2.3 ohms?" V = 10 x 2.3 = 23V
Find Current
I = V / R
"How much current flows through a 23-ohm heater at 230V?" I = 230 / 23 = 10A
Find Resistance
R = V / I
"What is the resistance of a load drawing 10A at 230V?" R = 230 / 10 = 23 ohms
Every other calculation in this guide builds on Ohm's law. When you measure earth fault loop impedance (Zs) and calculate whether the protective device will trip, you are applying Ohm's law: fault current = voltage / loop impedance (If = Uo / Zs). When you calculate voltage drop, you are applying V = I x R to the cable resistance. Master this equation and everything else follows.
03 · Apprentice Guide
The Power Triangle: P = V x I
The power formula tells you how much electrical power (in watts) a circuit delivers or consumes. Combined with Ohm's law, it gives you a complete toolkit for analysing any circuit.
P = V x I
Power (P, watts) = Voltage (V, volts) x Current (I, amps)
Rearranging this gives you:
I = P / V — use this to find the current drawn by a load when you know its power rating and the supply voltage. Example: a 3kW immersion heater at 230V draws I = 3000 / 230 = 13.04A. This tells you the minimum cable and protective device rating needed.
V = P / I — use this to find the voltage required for a given power and current. Less commonly used in day-to-day work but important for understanding transformer calculations.
By combining Ohm's law and the power formula, you can derive two more useful equations:
P = I² x R — power dissipated by a resistance carrying a current. Used in the adiabatic equation and for calculating heat generated in cables.
P = V² / R — power delivered to a resistance at a given voltage. Useful for calculating heater and lamp outputs.
In the real world, these calculations are used constantly. When a customer asks you to install an electric shower, you use I = P / V to determine the current drawn, then select the cable and protective device accordingly. When you are testing a circuit and need to verify that the protective device will clear a fault, you are applying these same principles.
04 · Apprentice Guide
Cable Sizing Basics
Cable sizing is one of the most important practical calculations you will perform as an electrician. Get it wrong and the cable overheats, the insulation degrades, and the installation becomes a fire risk. Get it right and the cable operates safely within its rated capacity for decades.
The cable sizing process follows these steps:
Determine the design current (Ib) — calculate the current the circuit will carry under normal conditions using I = P / V. For a 7.2kW electric shower at 230V: Ib = 7200 / 230 = 31.3A.
Select the protective device (In) — choose a protective device rated at or above Ib. For 31.3A, use a 32A MCB.
Apply correction factors — adjust the required current-carrying capacity for ambient temperature (Ca), grouping with other cables (Cg), and thermal insulation (Ci). The minimum required capacity is: Iz = In / (Ca x Cg x Ci).
Select the cable — look up the current-carrying capacity tables in BS 7671 Appendix 4 for the installation method and find a cable with It greater than or equal to Iz.
Check voltage drop — calculate the voltage drop for the cable length and current. Ensure it is within the permitted limits.
Check Zs — verify that the earth fault loop impedance at the furthest point is within the maximum for the protective device.
The correction factors are where many apprentices get confused. Think of them as penalties that reduce the cable's effective capacity. A cable in a hot loft (high ambient temperature) can carry less current than the same cable in a cool cellar. A cable bundled with other cables (grouping) generates more heat and must be derated. A cable covered in thermal insulation cannot dissipate heat effectively and must be derated further.
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Every cable has resistance. When current flows through it, some voltage is "dropped" across the cable, meaning the voltage at the load is lower than the voltage at the supply. This is voltage drop, and it is calculated using a version of Ohm's law:
Voltage Drop = (mV/A/m x Ib x L) / 1000
Where mV/A/m is the voltage drop per amp per metre (from BS 7671 tables), Ib is the design current, and L is the cable length in metres.
Worked Example
A 2.5mm² twin and earth cable supplies a 3kW immersion heater on a 15m run.
Design current: Ib = 3000 / 230 = 13.04A
mV/A/m for 2.5mm² (clipped direct, Table 4D5A): 18 mV/A/m
Voltage drop = (18 x 13.04 x 15) / 1000 = 3.52V
As a percentage of 230V: (3.52 / 230) x 100 = 1.53%
This is within the 5% limit for power circuits. Pass.
Voltage drop becomes a problem on long cable runs and with smaller cable sizes. If the calculated voltage drop exceeds the permitted limit, you have two options: use a larger cable (lower resistance per metre) or reduce the cable length (shorter route). In practice, you often need to upsize the cable by one size to bring the voltage drop within limits.
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Diversity is the principle that not all electrical loads in an installation operate at their maximum rating simultaneously. A house might have 30A of socket circuits, a 40A shower, a 30A cooker, and 10A of lighting, but they are never all running at full load at the same time. Diversity allows you to calculate a realistic maximum demand rather than simply adding up all the circuit ratings.
Common Diversity Factors (IET On-Site Guide)
Lighting — 66% of total lighting current demand. So if your lighting circuits total 10A, the diversified demand is 6.6A.
Heating and hot water — the full load of the largest appliance, plus the remaining appliances at various percentages depending on type and thermostat control.
Socket outlets — 100% of the largest circuit plus 40% of the remaining circuits. For two 32A ring circuits: 32A + (0.4 x 32A) = 44.8A.
Cooker — the first 10A at 100% plus 30% of the remaining current, plus 5A if the cooker control unit includes a socket outlet.
Electric shower — 100% (no diversity applied). Showers draw their full rated current whenever they are in use.
Understanding diversity is essential for designing domestic installations and for the 18th Edition exam. It determines the size of the main switch, the rating of the supply cable from the meter, and the maximum demand you declare to the Distribution Network Operator (DNO).
07 · Apprentice Guide
Prospective Fault Current: Will the Device Cope?
Prospective fault current (Ipf) is the maximum current that would flow if a short circuit or earth fault occurred at a given point in the installation. You need to know this because the protective device (MCB, RCBO, fuse) must be able to safely interrupt this current without damage.
How to calculate it — Ipf = Uo / Zs (or Ze for faults at the origin). For a typical domestic supply with Ze of 0.35 ohms: Ipf = 230 / 0.35 = 657A. This is well within the 6kA (6,000A) breaking capacity of standard domestic MCBs.
Why it matters — if the prospective fault current exceeds the breaking capacity of the protective device, the device could fail to interrupt the fault safely. This could cause an arc flash, fire, or explosion. In commercial and industrial installations with high fault levels, this is a critical design consideration.
Measurement — your multifunction tester can measure Ipf directly at the origin of the installation. The reading must be recorded on the EIC or EICR.
For most domestic installations, the prospective fault current is well within the breaking capacity of standard MCBs (typically rated at 6kA or 10kA). However, always measure and record it. In some situations, particularly in industrial installations or properties very close to a substation, the fault level can be much higher.
08 · Apprentice Guide
Tips for Calculation Questions in Exams
Calculation questions appear in the 18th Edition exam, Level 3 exam, C&G 2391, and the EPA. These tips will help you approach them confidently.
Write down what you know — before touching the calculator, list the values given in the question and identify which formula to use. This prevents the common mistake of rushing to calculate with the wrong equation.
Watch the units — kilowatts vs watts (multiply kW by 1000), millivolts vs volts (divide mV by 1000), megohms vs ohms. Unit errors are the most common cause of wrong answers.
Sense-check your answer — if you calculate a current of 500A for a domestic socket circuit, something has gone wrong. Develop a feel for what reasonable values look like.
Know which BS 7671 tables to use — for cable sizing, voltage drop, and maximum Zs values. The exam allows you to use BS 7671, so know where to find the tables quickly.
Practice regularly — calculation skills are like any other skill: they improve with practice and deteriorate without it. Do at least a few calculation questions every week throughout the apprenticeship.
09 · Apprentice Guide
Practice Calculations with Elec-Mate
Elec-Mate provides multiple tools to help you master electrical calculations at your own pace.
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Dedicated modules on Ohm's law, power calculations, cable sizing, voltage drop, diversity, and fault current. Each module includes theory, worked examples, and practice questions.
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Stuck on a calculation? Ask the AI tutor. It will walk you through the problem step by step, explain which formula to use, and show you how to rearrange equations. Like having a tutor in your pocket, available 24/7.
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