The standard voltage drop formula used with BS 7671 tables is straightforward:
VD = (mV/A/m × Ib × L) ÷ 1000
VD = voltage drop in volts
mV/A/m = millivolts per ampere per metre (from BS 7671 tables)
Ib = design current of the circuit in amperes
L = length of the cable run in metres
The mV/A/m value is the key figure. It represents the voltage drop per ampere of current per metre of cable length, expressed in millivolts. This value is specific to each cable type, conductor material, cross-sectional area, and whether the circuit is single-phase or three-phase. These values are tabulated in BS 7671 Appendix 4, in the "B" series of tables (4D1B, 4D2B, 4E1B, etc.).
For example, a 2.5 mm² copper twin and earth cable (flat thermoplastic, Table 4D5B) has a tabulated voltage drop of 18 mV/A/m for single-phase circuits. If this cable carries 20 A over a length of 25 metres, the voltage drop is:
VD = 18 × 20 × 25 ÷ 1000 = 9.0 V
This is 3.91% of 230 V — which passes the 5% power limit (11.5 V) but would fail the 3% lighting limit (6.9 V). If this were a lighting circuit, you would need to increase the cable to 4 mm².
The division by 1000 is necessary because the tabulated values are in millivolts, and we need the result in volts. Always remember to express the final answer as a percentage of the nominal supply voltage to compare against the BS 7671 limit: (VD ÷ 230) × 100 for single-phase, or (VD ÷ 400) × 100 for three-phase.